2006-11-30 01:51:07 · 7 answers · asked by chris.julian@btinternet.com 1 in Science & Mathematics ➔ Engineering
The average kettle is 1500-3000 Watts.
A=W/V
Amps = 2000/240 = 8.33
So approx 8.33 amps.
2006-11-30 01:56:53 · answer #1 · answered by E=MC2 3 · 0⤊ 0⤋
What ho.
There are not any amps in a kettle, hopefully only water.
If you mean what current does a domestic kettle draw from your mains supply, the answer is about 8A
This sounds daft, but if you go V=IR, then I= V/R.
Oh I can't be bothered
Look at the little label, which gives a figure in Watts.
Divide that by 240 in the UK, V is roughly 240.and the answer is roughly in amperes. Assuming unity power factor.
I have about a pint of amps in my kettle.
I shall use them to make coffee.
2006-11-30 02:32:00 · answer #2 · answered by Bob the Boat 6 · 0⤊ 0⤋
A 2 kilowatt electric kettle passes 8.69 Amps, & a 1.5 KW one passes 6.52 Amps. You just need to divide the Watts by the Voltage.
2006-11-30 07:03:30 · answer #3 · answered by ispooky2 2 · 0⤊ 0⤋
this is purely resistive circuit, using bimettalic elements to control heating. Average amperage for a 1000w kettle would be around 4 Amperes using the formula P=VI from this formula you can approximate the current which is I=P/V (the source is AC so there is a slight difference in the actual current)
2006-11-30 02:04:26 · answer #4 · answered by HkHR 2 · 0⤊ 0⤋
I don't condone davemc 746 actions in cutting them into pieces as I think it cruel, but he is correct.
Those amps bring tears to my eyes whenever I meet them.
2006-11-30 02:59:18 · answer #5 · answered by Anonymous · 0⤊ 0⤋
only the red amps sting
2006-11-30 03:31:55 · answer #6 · answered by chillpill9933 1 · 0⤊ 0⤋
I aint got amps..I got scale!
2006-11-30 01:54:53 · answer #7 · answered by Anonymous · 1⤊ 0⤋