2006-11-29 13:58:11 · 12 answers · asked by doulasc 2 in Food & Drink ➔ Non-Alcoholic Drinks
yes I have seen coca cola with lime it is still being made, I am not sure of the others though
2006-11-30 01:55:23 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Yes, Coca Cola With LIme, Pepsi Lime, Pepsi Lemon are still being made. Pepsi Vanilla And Coke Vanilla, I'm sure about. I've not seen them at the market, nor even in drug store refrigerators, for at least 18 months.
2006-11-29 14:06:49 · answer #2 · answered by Anonymous · 1⤊ 0⤋
No to #1 sure to #2 #3 I think is simply too strange for coke. However I would be incorrect how about a lemon coke I had one at a 50's variety resturant and it was first-rate. It was very tasty. Alot higher then the coke with lime.
2016-08-09 23:53:10 · answer #3 · answered by velo 4 · 0⤊ 0⤋
Lime ones are still out but they stopped making the vanilla one ages ago
2006-11-29 14:05:39 · answer #4 · answered by ♪♫~Paranoid~♫♪ 3 · 1⤊ 0⤋
Yup yup all of them that I know of,I had a Pepsi with lime the other day actually
2006-11-29 14:03:34 · answer #5 · answered by Anonymous · 0⤊ 0⤋
i still think they are although i havent seen it and i have seen pepsi lime not sure bout the vanilla though
2006-11-29 14:03:37 · answer #6 · answered by Bean 3 · 1⤊ 0⤋
I don't think so. I don't think it was selling that good. I tried it once and it was nasty. It might just be a summer promotion thing. It might be back out next summer. Pepsi vanilla is still out had one yesterday.
2006-11-29 14:07:36 · answer #7 · answered by **baby~doll** 3 · 1⤊ 0⤋
no to #a million sure to #2 #3 i imagine is purely too unusual for coke. yet i'd be incorrect how about a lemon coke I had one at a 50's variety resturant and it became large. it became very tasty. alot extra useful then the coke with lime.
2016-11-29 23:07:26 · answer #8 · answered by ? 4 · 0⤊ 0⤋
yes, yes, no
I MISS PEPSI VANILLA AND BLUE!!!
2006-11-29 14:05:48 · answer #9 · answered by flylikepowell 2 · 1⤊ 0⤋
hhhh
2006-11-29 14:30:23 · answer #10 · answered by Anonymous · 0⤊ 1⤋