to who breake up or new lovers
2006-11-29 11:00:18 · 10 answers · asked by hashem a 2 in Family & Relationships ➔ Singles & Dating
Hi! I think love can be painful and also make you happy. Love's important. Without it, we die. Sometimes, when we love, we get hurt, but I think thats a risk we should take. But, when you're in a relationship that hurts more than it makes you feel happy, then I'd wonder if its really love or may be rather a dependency and/or an unhealthy relationship. In a loving relationship, happiness outweighs pain. Both is there, but happiness should really be dominant. Wishing you much happiness and love! Gini ;-)
2006-11-29 11:07:18 · answer #1 · answered by Anonymous · 0⤊ 0⤋
I'm not sure i understand the question. But some love ends up in pain, and some in happiness. But all pain leads to happiness eventually. You don't want to be with someone who is not good for you.
2006-11-29 19:02:48 · answer #2 · answered by Miss E 2 · 0⤊ 0⤋
Let's put it this way: Love = misery. Singlehood = total happiness forever.
2006-11-29 21:01:57 · answer #3 · answered by Anonymous · 0⤊ 0⤋
love is happiness and painful
but the saying goes " I rather have love and lost then to never have love at all"
2006-11-29 19:04:00 · answer #4 · answered by BROWNLYN 5 · 0⤊ 0⤋
Broken love is very painful.You really never forget that person.
2006-11-29 19:03:24 · answer #5 · answered by George K 6 · 0⤊ 0⤋
huh i missed the question but if this helps its painful very painful
2006-11-29 19:04:48 · answer #6 · answered by *Living a {{ღяøM@N!Cღ}} Tragity* 5 · 0⤊ 0⤋
love is painful when the heart is broken...
2006-11-29 19:03:41 · answer #7 · answered by mitchp5254 2 · 0⤊ 0⤋
No, but your grammar and spelling is.
2006-11-29 19:02:00 · answer #8 · answered by Anonymous · 0⤊ 0⤋
Since ORGASM = LOVE
and HAPPINESS = LONG TIME + SPENDING MONEY
The answer is "no"
2006-11-29 19:01:59 · answer #9 · answered by drsteve362005 6 · 0⤊ 1⤋
Please translate all of that into comprehensible English.
2006-11-29 19:02:10 · answer #10 · answered by Anonymous · 0⤊ 0⤋