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This process works relying that V=IR, wich is Voltage= Amps times Ohms. Ohms are a measurement that measures resitance, for example, a lightbulb has a certain Ohm rating, and amps would be how much the batteries produced. So, by adding more batteries to the circut, depending on the circuit, you could increase the voltage. For example, let's say that you have 5 lightbulbs, each with 1 Ohm, and you have 2 batteries, producing 3 amps each. Here, we simply multiply (1*5)(2*3), which equals 30. Therefore, V=30 in this circuit. However, this would only work in a parallel circuit, which means that the batteries have to be parallel to each other and the lightbulbs. Sorry for the long response, I hope it answered your question!

2006-11-28 23:23:30 · answer #1 · answered by Steve M 1 · 0 0

Connecting batteries in series increses the voltage but the current remains the same.

Connecting the batteries in parallel increases the current but the voltage remains the same.

-----

Think of the electrical path between the positive and the negative sides of the battery as a roadway in the following illustration

The roadway has two properties. It is a certain width (current) and has traffic (voltage).

When two or more batteries are connected in series, that is the negative from one is connected to the positive of another in this fashion
----[+ -][+ -][+ -]-----
The amount of traffic (voltage) is the sum of the voltage of each battery but the road width (current) remains the same.

So; more electrons moving but with the roadway staying the same width, the voltage is increased but the current is the same.

When the batteries are connected in parallel, all the positive ends and the negative ends are connected like this,
[+ -]
[+ -]---
[+ -]
the amount of traffic (voltage) remains the same but the road width (current) has increased.

Thus, there are more electrons moving, since the current path is increased, yet the voltage does not increase.


In both instances the power is the same. (P = I * E)
P = power (watts). I = current (amperes), E = volts

To prove this, let's say that each battery is rated for 15 volts and 2 amperes of current.

Connecting 3 in series would result in;
15V * 3 = 45V total (voltage was tripled in this configuration)
and still at 2 amperes.
so:
P = IE; 45*2 = 90 watts.

Connecting 3 in parallel would result in;
15V would remain the same.
2 amperes * 3 = 6 amperes total (current was tripled in this configuration)
So:
P = IE; 6*15 = 90 watts.

2006-11-29 00:58:15 · answer #2 · answered by Dee_Smithers 4 · 1 0

A battery is a voltage source, also known as "potential". This means it contains the energy to force current to flow through a closed loop.

Thinking back to other things you may have learned about physics and potential energy: if you were to stand on a step, you'd have some amount of "potential", based on how high you were above the ground (basically due to gravity). If you were to climb up to a higher step, you'd have more potential; if you were to move sideways to another staircase without increasing your distance from the ground, your potential would remain the same.

Same thing happens with batteries. To climb up the "potential ladder", you need to add them together (in series, like climbing a stair). If you put them in parallel (moving from one stair to another), you don't gain any potential energy.

Current is drawn from the batteries because of Ohm's Law, which basically states that the sum of potential in a circuit is zero. It also says that voltage is proportional to current and resistance (V = I * R). Without a load (a resistor or light bulb or something else) connected to the battery, there will be no current flow.

If you add batteries in series, voltage (V) increases. Resistance (R) doesn't, so to maintain the relationship the current (I) must also increase.

If you add batteries in parallel, voltage (V) stays the same. Resistance (R) stays the same, so current (I) must also stay the same.

2006-11-29 00:56:45 · answer #3 · answered by CanTexan 6 · 0 0

-In series, i.e. one after the other, voltage increases by the voltage of the battery added while current stays about the same. If added in parallel, i.e. all the +'s connected to the positive side ant all the -'s the same way, the voltage stays the same but the curent flow increases. Think of it like water - Voltage is like the water pressure, how hard it shoots out, while current is like the size of the tap; how much water flows through.

2006-11-28 23:26:01 · answer #4 · answered by AmigaJoe 3 · 0 0

Just think about it. If you put multiple batteries in series, the voltages add. For a given resitance connected to the batteries, the higher voltage means higher current. Keep in mind you can't put them in series.

2006-11-28 23:16:18 · answer #5 · answered by Gene 7 · 0 0

A connect the (+) contact of a battery with the (-) contact of the subsequent battery: you shall have more advantageous voltage (= the sum of voltages contained in the set of batteries) than with absolutely one battery. B connect the (+) contacts of each and every battery mutually. Do a similar for the (-) contacts. You shall have more advantageous modern than that of only one battery. C a mixture of A and B shall provide you with a mixture of both more advantageous voltage and modern than those presented with the help of one battery on my own. in case you ought to have some correct mixture of voltage and modern, you shall have a metering device to envision the voltage and modern of your gadget. understand that lengthy, skinny wires to boot as undesirable (dirty!) contacts between batteries devour some skill it rather is likewise a reason to have a metering device in case you ought to attain some very precise values of voltage and modern.

2016-11-27 20:50:55 · answer #6 · answered by ? 4 · 0 0

Increase Voltage From Battery

2017-02-23 15:10:40 · answer #7 · answered by nicolaevitsch 4 · 0 0

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