a) the currents passing through the two resistors are identical.
b) the voltage drops across the two resistors must add to equal the voltage from the supply.
c) the current through one resistor is equal to (-1) times the current in the other resistor.
2006-11-26 06:51:43 · 9 answers · asked by gbmac722 2 in Science & Mathematics ➔ Engineering
using KCL (current law), A is corrent.
using KVL (voltage law), B is correct
C doesn't make any sense, and you can support that with the definition of the KCL.
2006-11-26 08:53:18 · answer #1 · answered by B W 2 · 1⤊ 0⤋
C. Since they are in series the entire current must go through each, making them equal and when in series the total V across resistors must equal total V across power source.
2006-11-26 06:55:00 · answer #2 · answered by zzzzz 2 · 1⤊ 0⤋
C is false. The current through one resistor in series will be the same as the current through the other.
2006-11-26 06:53:49 · answer #3 · answered by DanE 7 · 2⤊ 0⤋
Formula V=I/R 14v=I/6.3 or I =14/6.3 I=2.2amp Current should remain constant. V=IR > V=9.1* 2.2amp > V= 20.0 Vtotal=34.0V
2016-03-29 09:53:25 · answer #4 · answered by Anonymous · 0⤊ 0⤋
"a" and "c" contradict each other, so it must be one of them which is false (based on the law of noncontradiction). applying kirchoff's current law reveals that "a" is true and "c" is false.
2006-11-26 07:01:15 · answer #5 · answered by Anonymous · 0⤊ 0⤋
c is false
2006-11-26 06:54:42 · answer #6 · answered by tamana 3 · 0⤊ 0⤋
c is false
2006-11-26 06:53:50 · answer #7 · answered by DadOnline 6 · 0⤊ 0⤋
c
2006-11-26 06:54:01 · answer #8 · answered by hogie0101 4 · 0⤊ 0⤋
C
2006-11-26 06:59:02 · answer #9 · answered by Anonymous · 0⤊ 0⤋