2006-11-23 23:59:23 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
| A - I(lamda)| = 0 ==> eigenvalue ...
lamda is an eigenvalue...
solve the matrix first
2006-11-24 00:20:13 · answer #1 · answered by nasiaq 2 · 0⤊ 0⤋
In a functional equation (say y = f(x) ) there will always be some value of x for which f(x) = x. For example y = 5x-4, If you put in a 1 for x, you'll get a 1 for y. Values which cause a function to return the same value are called the 'kernal' of the function. When you extend this idea to a vector space, you find that any vector function (which accepts a vector as the argument and returns a vector as the result) also has a 'kernal' of vectors which all 'point' in the same direction and may have different magnitudes. The ratio of the magnitude of the transformed vector to the original vector is called the eigenvalue associated with each vector, (The vectors are called, not too surprisingly, the eigenvectors.) Eigen is an old German word meaning 'singular' or 'by itself'.
Doug
2006-11-24 08:32:26 · answer #2 · answered by doug_donaghue 7 · 0⤊ 0⤋
go to this link: www.physlink.com/education/ask expert.
Click on search and type eigen values.
I have yet to see a better answer!
2006-11-24 08:16:42 · answer #3 · answered by quark_sa 2 · 0⤊ 0⤋
I want not to rewrite the text on the link Follow it very good source
2006-11-24 08:12:35 · answer #4 · answered by maussy 7 · 1⤊ 0⤋
they are the zeroes of a differantial equation
2006-11-24 09:16:04 · answer #5 · answered by koki83 4 · 0⤊ 0⤋
an "allowed" value.
2006-11-24 08:10:46 · answer #6 · answered by Morgy 4 · 0⤊ 0⤋