When it's ln something you put the diravtive of the bit in brackets on top of the bit in brackets not differentiated. I can't quite remember what the derivitave of cosx is but I think it's either sinx or -sinx.
So it would be something like...
sinx
____
cosx
Please check a maths text book before you base any test answers on my answer! Hope this helped.
2006-11-23 21:52:52
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answer #1
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answered by purpleboy 1
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You can't, as far as I am aware, without doing it numerically. Other than reasonably special cases, you would only be able to integrate it if the inside part, differentiated, occurred somewhere. But in this case, it doesn't, so its not really possible.
2006-11-23 21:16:20
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answer #2
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answered by stephen m 4
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you use integration by parts
you put u = ln (cosx) du = tg(x)
v= x dv = dx
than udv = uv - vdu
udv = x lncosx - x tg(x)
The integral of tg (x) = -ln( cosx) so
2006-11-24 00:25:24
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answer #3
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answered by maussy 7
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Just tips, I don’t remember details. As exp(x*i)=cos(x)+i*sin(x) you first consider integral of ln(exp(x*i))=i*x on complex plane around particular point [0,0]
2006-11-23 22:06:17
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answer #4
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answered by Anonymous
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i will integrate it if u integrate f((x)^(x))dx
2006-11-23 21:22:56
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answer #5
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answered by sidharth 2
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