When the rubber band in a slingshot is stretched, it obeys Hooke's law. Suppose that the "spring constant" for the rubber band is k = 54 N/m. When the rubber band is pulled back with a force of 7.9 N, how far does it stretch? (answer in meters)
2006-11-23 17:06:24 · 3 answers · asked by Jim E 1 in Science & Mathematics ➔ Physics
Since you are talking about a slingshot, the force is halved for each side.
3.95 N/54N/m = 0.073 m
2006-11-23 17:13:05 · answer #1 · answered by Helmut 7 · 1⤊ 0⤋
The formula for the force in a Hooke's law spring with spring constant k and displacement x is F = -kx, negative because the force opposes displacement. So just divide the applied force by the spring constant to get the distance, because F = -kx ==> x = F/(-k).
2006-11-23 17:08:48 · answer #2 · answered by DavidK93 7 · 0⤊ 0⤋
.146M
2006-11-26 03:11:14 · answer #3 · answered by Anonymous · 0⤊ 0⤋