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The hierchy of arithmatic operators, addition, subtraction, multiplication, division and brackets when trying to solve simplification like (3+7)-76*122/77. The memory aid is BODMAS. I want to know the full form of BODMAS.

2006-11-23 16:47:49 · 11 answers · asked by Arnab Kumar D 1 in Science & Mathematics Mathematics

11 answers

Brackets, Orders, Division, Multiplication, Addition, Subtraction.
In some countries its BEDMAS, where E is exponents.

2006-11-23 16:49:12 · answer #1 · answered by stephen m 4 · 4 0

Brackets, Orders, Division, Multiplication, Addition, Subtraction

2006-11-23 21:10:23 · answer #2 · answered by David - Joseph 2 · 0 0

B - Bracket
O - Order/ Of
D - Division
M - Multiplication
A - Addition
S - Subtraction

2006-11-23 18:17:49 · answer #3 · answered by Akilesh - Internet Undertaker 7 · 0 0

Bodmas Full Form

2017-01-13 20:26:52 · answer #4 · answered by houff 4 · 0 0

try PEMDAS:
Parenthesis
Exponents
Multiplication
Division
Add
Substraction

2006-11-23 20:20:36 · answer #5 · answered by marcos m 2 · 0 0

B bracket,O order of operation,D division,M multiplication,A addition and S subtraction....

2013-10-19 06:37:21 · answer #6 · answered by CA Rajesh Gupta 1 · 0 0

'BODMAS' stands for 'Bracket()', 'Of(*), 'Division(/)', 'Multiplication(*)', 'Addition(+)', 'Subtraction(-)'.
we have to execute all question by this method as per the specified order.
example:
solve
(3+7)-78*122/77
as per the rule of BODMAS we first solve the bracket the expression thus becomes
10-78*122/77
now comes 'DIVISION'
10-78*1.58
now multiplication
10-123.24
now subtraction
=-113.24(answer)

2006-11-23 21:45:01 · answer #7 · answered by manu 2 · 1 0

brackets
order / of
division
multiplication
addition
subtraction

2006-11-23 16:49:51 · answer #8 · answered by raj 7 · 2 0

B for brackets,O for of,D for division ,M for multiplication,A for addition and S for subtraction.These are the sequences to be followed in simplification

2006-11-23 19:41:04 · answer #9 · answered by alpha 7 · 0 0

B - BRACKET
O - ORDER/OF
D - DIVISION
M - MULTIPLICATION
A - ADDITION
S - SUBTRACTION
---------------------------------------------------------------------
WE CAN SOLVE THE SUM -
(3+7)-76*122/77
10-76*122/77
10-76*1.58
10-120.08
110.08
--------------------------------------------------------------------

2006-11-23 18:28:13 · answer #10 · answered by bhat 1 · 0 1

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