Charles defined a new operation on pairs of ordered pairs of intergers as follows (a,b) and (c,d) = ac +bd divided by ab - cd. what is the value of (2,1) and (3,4)
2006-11-23 14:42:40 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Here is how you do it:
(2,1) and (3,4) = [(2)(3) + (1)(4)]/(2)(1) - (3)(4)
= (6 + 4)/(2-12)
= 10/-10
= -1
Tada
2006-11-23 15:00:19 · answer #1 · answered by Harrison S 1 · 1⤊ 0⤋
Given (a,b)(c,d)=(ac+bd)(ab-cd)
Therefore,(2,1)(3,4)=(2X3+1X4)(2X1-3X4)
=(10)(-10)
=-100
2006-11-23 23:09:19 · answer #2 · answered by alpha 7 · 0⤊ 2⤋
I agree with Harrison S.
The answer will be -1.
2006-11-23 23:41:27 · answer #3 · answered by LetMe_FindOut 2 · 0⤊ 0⤋
add it u should get 10 and dats the answer
2006-11-23 22:50:53 · answer #4 · answered by combs 5 · 0⤊ 1⤋
Plug and chug.
2006-11-23 22:45:24 · answer #5 · answered by modulo_function 7 · 0⤊ 0⤋