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for adding the fractions 4/15 , 1/12 and 3/8

2006-11-23 14:35:51 · 10 answers · asked by Anonymous in Science & Mathematics Mathematics

10 answers

120

2006-11-23 14:38:32 · answer #1 · answered by Lola76 5 · 0 0

hi,
regarding least common denominator.....

In mathematics, the lowest common denominator or least
common denominator (abbreviated LCD) is the least
common multiple of the denominators of a set of vulgar
fractions.


It is the smallest (non-zero) number that is a multiple of
the denominators.
example.... lcd for 1/2 and 1/4 is 4 but that for 1/2 and 1/3 is 6..


By using this (or any multiple of it) as a denominator, it
enables addition, subtraction or comparison of fractions

4/15 +1/12 +3/8
= 32/120+10/120+45/120
=87/120

2006-11-23 22:55:39 · answer #2 · answered by netizen_india 1 · 0 0

4/15+1/12+3/8=?

4/15x8/8=32/120
1/12x10/10=10/120
3/8x15/15=45/120

32/120+10/120+45/120=87/120
You add the numerator and the denominator stay the same. So the denominator is 120.

2006-11-23 23:57:34 · answer #3 · answered by LetMe_FindOut 2 · 0 0

It is the LCM of 15 and 8.
Since 15 = 3*5
8 = 2*2*2
these 2 numbers have no factor in common.
So the answer is 15*8 = 120.

2006-11-23 22:52:15 · answer #4 · answered by steiner1745 7 · 0 0

120

2006-11-23 22:40:12 · answer #5 · answered by Erik N 2 · 0 0

120

2006-11-23 22:38:52 · answer #6 · answered by janellie 2 · 0 0

step 1. prime factorise the denominators
15=3*5
12=2*2*3=2^2*3
8=2*2*2=2^3

step 2. take the highest power of the commomn factors
3,5 and 2^3


step3. multiply
3*5*2^3=120

step4. yourLeast Common multiple is 120

2006-11-23 22:43:24 · answer #7 · answered by raj 7 · 0 0

4/15 , 1/12 and 3/8
15=3*5
21=2^2*3
8=2^3
LCD=2^3*3*5=120
4/15=32/120
1/12=10/120
3/8=45/120

2006-11-24 00:06:29 · answer #8 · answered by yupchagee 7 · 0 0

Least Common denominator is the LCM of the denominators
Here,the denominators are 15,12 and 8
Their LCM=120
Least Common Denominator is 120

2006-11-23 23:29:08 · answer #9 · answered by alpha 7 · 0 0

it's 120. you have to find a number that all the denominators would go into equally.

2006-11-23 22:43:10 · answer #10 · answered by sportzgurl 3 · 0 0

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