the undertaker will fight kennedy soon what will happen to him?
2006-11-23 13:35:22 · 8 answers · asked by Anonymous in Sports ➔ Wrestling
He will get his butt kicked, if the script writers want that outcome.
Kennedy has the charisma to go ahead in the business, be hopes he can at least put over a good match as if not he will go the way of all past wanna be's end up ECW or TNA..or Circuit LOL...Cheers
2006-11-23 13:42:16 · answer #1 · answered by Whoops 5 · 0⤊ 0⤋
I think Kennedy will win. My guess is someone will get involved, so the fued will end. Kennedy is getting a big push and I wouldn't even be suprised if he gets a win at the Royal Rumble, maybe not this year but at least the year after that. It also looks like Kane and Undertaker are going to fued again because their last fued never really got settled and kinda went unfinished. I wouldn't be suprised if Kane makes another heel turn and comes out and takes Taker out. He might not make a heel turn yet but it will most likely happen again.
2006-11-24 01:44:28 · answer #2 · answered by average_joe397 4 · 0⤊ 0⤋
Kennedy will cheat to win the 1st blood match. The worlds strongest man will make a surprise comeback and give him outside interference
2006-11-24 02:07:35 · answer #3 · answered by xblee1 5 · 0⤊ 0⤋
He will get a TOMESTONE on a chair like how Undertaker debut agianest Hulk Hogan for the WWE Championship
2006-11-23 22:59:20 · answer #4 · answered by Malik 4 · 0⤊ 0⤋
taker is gonna kill him
like jbl said: smackdown is gonna lose one hell of a superstar if kennedy don`t leave undertaker alone
2006-11-24 12:22:00 · answer #5 · answered by *nicole* loves *joe b* 3 · 0⤊ 0⤋
Undertaker will bloody him up real good
2006-11-23 22:07:08 · answer #6 · answered by I_R_A_7 3 · 0⤊ 0⤋
tombstone tombstone tomestone for mr.kennedy all the way
2006-11-23 21:53:11 · answer #7 · answered by jamaican babe 7 · 0⤊ 0⤋
he will win because he is. mrrrrrrrrrrrrr. keneddyyyyyyyyyyyyyyyyyyyyyyyyy
kenedyyyyyyyyyyyyyyyyyyyyyyyyyy
2006-11-23 21:44:48 · answer #8 · answered by mets= k-rod 3 · 0⤊ 0⤋