Can somone give me how to get the distance between two points on a coordinate plane? Distance formula?

Answer 1

Distance Formula:

root((x1-x2)^2+(y1-y2)^2)

for points (x1,y1) and (x2,y2)

You can switch x1 and x2 ONLY if you also switch y1 and y2 in the formula.

Answer 2

The distance between two points (x1, y1) and (x2, y2) is:
d = √[(x2 - x1)² + (y2 - y1)²]

Example: Find the distance between (-6, -2) and (3, 1).
d = √[(x2 - x1)² + (y2 - y1)²]
d = √[(3 - (-6))² + (1 - (-2))²]
d = √[(3 + 6)² + (1 + 2)²]
d = √[(9)² + (3)²]
d = √(81 + 9)
d = √90 = √9 * √10 = 3√10 ≈ 9.487 units

Answer 3

1.jot down the coordinates of both the points (x1,y1),(x2,y2)
2.find the difference between the x coordinates (x1-x2)
3.square it=(x1-x2)^2
4.find the difference between the y coordinates (y1-y1)
5.square it =(y1-y2)^2
6.add the squares of the differences(x1-x2)^2+(y1-y2)^2
7.find the square root [(x1-x2)^2+(y1-y2)^2]^1/2
8.step no 7 gives you the distance between the points

Answer 4

The distance between (a,b) and (c,d) is sqrt((a-c)^2 + (b-d)^2).
If you just draw a right angled triangle with the hypotenuse between those points, you'll see the lengths of the sides are a-c and b-d, so then you just use pythagoras.

Answer 5

D=The square root of(X2-x1)^2+(Y2-Y1)^2
Hope this solves your problem.

Answer 6

D = sqrt((x2 - x1)^2 + (y2 - y1)^2)

Answer 7

d=square root of [(x2-x1)^2 + (y2-y1)^2]

Answer 8

square root of [(x2-x1)^2 + (y2-y1)^2]

Answer 9

if the points are (x1,y1) and (x2,y2)

answer is sqrt((x1-x2)^2 + (y1-y2)^2)

Answer 10

The distance between points P(x, y) and Q(a, b) is
PQ = √[(x - a)² + (y - b)²].