can anyone help me with trigonometry right triangles?

Question

I have a right triangle that is drawn to the left with the right angle at the right and it gives me a number for the hypotenuse and a number for the opposite side but I need to know the adjacent side. If anyone could please help me I would appreciate it.thanks

Answer 1

Pythagorean theorem:
for a right triangle, with sides 'a' and 'b' adjacent to the right angle, and hypotenuse 'c' opposite the right angle,
a^2+b^2=c^2
("a squared plus b squared equals c squared")
solving for one of the non-hypotenuse sides:
a = (c^2-b^2)^(1/2)
("a equals the square root of (c squared minus b squared)")

Answer 2

Pythagoras - for a right-angle triangle sides a,b, and hypotenuse c):

a^2 + b^2 = c^2 (^2 means squared).

so if you know a and c
b^2 = c^2 - a^2
b = Sqrt(c^2 - a^2)

Pretty straight-forward.

Answer 3

[(hypotenuse)^2] - [side]^2 = [adjacent side]^2
take the sqr root of adjacent side and that will be the answer