I know it is 5n - something
2006-11-23 08:57:41 · 11 answers · asked by x1gemma1x 1 in Science & Mathematics ➔ Mathematics
Regroup and add. You got the 5n, so you should be able to get the other part!
n + n - 1 + n - 2 + n + 7 + n - 11 =
n + n + n + n + n - 1 - 2 + 7 - 11 =
5n - 7
Notice that -1 -2 - 11 = -14, add 7 to it and you get -7
NRT
2006-11-23 09:00:29 · answer #1 · answered by New Rule Tomorrow 2 · 1⤊ 0⤋
n + n - 1 + n - 2 + n + 7 + n - 11=5n-7
2006-11-23 18:26:32 · answer #2 · answered by yupchagee 7 · 0⤊ 0⤋
The something is -1 - 2 + 7 -11. So the answer is 5n - 7.
2006-11-23 18:09:56 · answer #3 · answered by steiner1745 7 · 0⤊ 0⤋
Addition of scalars is commutative. So it's 5n - 1 - 2 + 7 - 11 = 5n -14 +7 = 5n -7
2006-11-23 17:01:40 · answer #4 · answered by Edgar Greenberg 5 · 0⤊ 0⤋
n + n - 1 + n - 2 + n + 7 + n - 11
= n + n + n + n + n + 7 - 1 - 2 - 11
= 5n + 7 - 14 (+7 - 14 = opposite of + 14 - 7 = opposite of + 7 = - 7)
= 5n - 7
2006-11-23 17:00:31 · answer #5 · answered by Wal C 6 · 0⤊ 0⤋
And the something is -1-2+7-11 = -7. So 5n-7.
2006-11-23 17:00:16 · answer #6 · answered by stephen m 4 · 0⤊ 0⤋
Add like terms
(n+n+n+n+n) + (-1+-2++7+-11)=
5n-7
2006-11-23 21:45:37 · answer #7 · answered by lulu 3 · 0⤊ 0⤋
Well, inorder to solve this problem you have to combine like terms. so you'll take n+n-1+n-2+n+7+n-11and combine the variables and the whole numbers.
n+n-1+n-2+n+7+n-11=(n+n+n+n+n)+(-1+-2+7+-11)
n+n-1+n-2+n+7+n-11=(5n)+(-7)
n+n-1+n-2+n+7+n-11= (5n-7)
2006-11-23 17:17:48 · answer #8 · answered by Carpe Diem (Seize The Day) 6 · 0⤊ 0⤋
n+n+n+n+n =5n
-1-2+7-11 = -7
answer: 5n-7
2006-11-23 17:17:45 · answer #9 · answered by dragon888c 2 · 0⤊ 0⤋
let's simplify this down.
(n+n+n+n+n)+(-1-2+7-11)
(5n)+(-3+7-11)
(5n)+(4-11)
5n-7
2006-11-23 17:03:36 · answer #10 · answered by Hawk 2 · 0⤊ 0⤋