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combustion, cracking, fractional distillation, reduction, reforming?

2006-11-23 07:30:12 · 13 answers · asked by Anonymous in Science & Mathematics Chemistry

13 answers

fractional distillation

2006-11-23 07:31:33 · answer #1 · answered by Anonymous · 1 0

Fractional distillation

2006-11-26 08:18:54 · answer #2 · answered by lenpol7 7 · 0 0

Fractional distillation. It relies upon a mix of hydrocarbons having different boiling/codensing points. the mix is heated strongly and in a fractionating column the different fractions will condense at different points away from the source of heat and can be tapped off so seperating the mixture. The lightest fractions will not condense and disappear as gas at the top, the heaviest fraction condenses at a high temperature at the bottom of the column ( bitumen in the case of crude oil)

2006-11-23 07:39:39 · answer #3 · answered by wolfie 2 · 0 0

Either B or A B) for the physical you could use distillation to separate the two but the alcohol part would only be able to reach about 90% alcohol and 10% water.(this is due to the fact they form an azeotrope). You would have to use a drying column with a salt like sodium sulfate to remove the rest of the water A) to chemically separate the two you could use ion-exchange resins to to absorb the alcohol from the water by chemically binding it and release it into a solvent with which it does not form a azeotrope and distill it. This is a good way to get pure alcohol. Yes, you have to use a physical process to get pure alcohol by distillation but at that point you have already separated the alcohol from the water

2016-05-22 23:48:30 · answer #4 · answered by Anonymous · 0 0

Fractional distillation.

Combustion = burning in the presence of oxygen.
e.g. C3H8 + 5O2 --> 3CO2 + 4H2O

Cracking = breaking down of a large hydrocarbon into smaller ones in the presence of heat.
e.g. C12H26 --> C3H6 + C4H8 + C5H12

Fractional distillation = distillation with the extra column for re-condensing

Reduction = gaining of hydrogen to form a different compound.
e.g. C2H4 + H2 --> C2H6

2006-11-26 03:04:52 · answer #5 · answered by Kemmy 6 · 0 0

Fractional Distillation - definately ive just done this in chemistry yesterday

2006-11-23 08:40:46 · answer #6 · answered by Perfect-Angel84 2 · 0 0

More than one way of separating hydrocarbons. Distillation is possible in most cases, catalytic cracking works well with oil. I have personally used a catalytic dehydrogenator to remove hydrogen from aromatic compounds such as alkyl and alkylidene hydrocarbons.

Fractional distillation can be done by batch methods, or continuous processes such as LUWA thin-film evaporators. Then you can use FFEs (falling film evaporators) or CFEs (climbing film evaporators) according to the behaviour of the distillate.

There are even more esoteric methods such as Ion Exchange Columns and similar.

So many ways of achieving effective separation, depending largely on the materials to be separated.

2006-11-23 07:43:07 · answer #7 · answered by Phish 5 · 0 1

by distilation this is the process to séparate hydrocarbon only by difference of température if you want to séparate natural gas wich consiste of nitrogéne methane ethane propane butane pentane or c1,c2, c3,c4,c5 you must cooling down the feed of the distilation column at -60°c keep the head of this tower at -98 and the bottom at +128 °c this is the firt stage which gives us methane on the t op and the others product togetherand the bottom you recycle to refeed more towers to obten the others ones séparetly we named this prosses "fractionnement"

2006-11-23 08:09:02 · answer #8 · answered by BELISK 1 · 0 0

THE PROCESS NORMALLY USED IS FRACTION DISTILLATION BECAUSE THERE ARE NUMEROUS CONSTITUENTS OF HYDROCARBON WITH BOILING PT> DIFFERENCE OF AROUND 10-20 k. SO, TO GET EVERY CONSTITUENT SEPRATLY WE USE FRACTIONAL DISTILLATION COLUMNE.

2006-11-23 07:58:52 · answer #9 · answered by gaufire 1 · 0 0

fractional distillation is the separation
combustion is the burning
cracking is the shortening chain length

2006-11-23 07:42:14 · answer #10 · answered by Andy J 1 · 0 0

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