i have 2 batteries and when i connect them to one bulb i get a strong emission of light. if i connect 3 bulbs to the same circuit the light output decreases. how can i keep this output the same for 3 bulbs as for 1?
2006-11-23 07:12:37 · 15 answers · asked by donna k 1 in Science & Mathematics ➔ Physics
You need to wire them in parallel, with wire heavy enough for the total current and also have a battery that can deliver the current required at the voltage required without voltage drop. You don't state the battery voltage or the lamp wattage, so I cant work it out for you!
(I take it that you want EACH of the three bulbs to be as bright as one single one?)
2006-11-23 07:24:01 · answer #1 · answered by jayktee96 7 · 2⤊ 1⤋
The battery will produce an output that will remain pretty constant. The more bulbs you add, the more this output has to be shared out. The only way you will maintain a constant amount of light from all 3 bulbs, is to use three separate batteries, one for each bulb. Or, if not bright enough, two batteries per bulb.
2006-11-23 08:31:03 · answer #2 · answered by Andrew 3 · 0⤊ 1⤋
there are alot of misguided people in this thread. the answer can never be series. listen to the electricians who already posted that the correct way to do this is to wire the bulbs in parallel.
if you only used one bulb, the potential difference (pd) across it would be the battery voltage, V. the only way for you to get same brightness for 3 bulbs at the same time is if you wired the bulbs in parallel so that all 3 bulbs would EACH be powered by V. if you used series, then each bulb would have a pd of one third V (power across would be one ninth) and you dont want that.
the advantage of using series formation is that battery life is longer than in parallel formation by a factor of 9.
2006-11-23 07:46:51 · answer #3 · answered by Anonymous · 3⤊ 0⤋
You need to connect them in series, this provides the same voltage to all the bulbs and thus the same current, therefore same brightness.
(Technically the voltage won't be exactly identical to if there was only one bulb because the battery will have an internal resistance, which means that the more current you draw from the battery the less voltage you can get out of it, however the brightness of each of the three bulbs will be very close to as if there was only one bulb)
2006-11-23 07:24:44 · answer #4 · answered by Paul E 2 · 1⤊ 2⤋
I'm not clear, do you mean the three bulbs together to give off the same amount of light as one bulb, or three bulbs each individually as bright as one bulb, in series you will dim each bulb but I don't know if this will equal one bulb, just give it a try.
2006-11-24 06:32:54 · answer #5 · answered by bo nidle 4 · 0⤊ 0⤋
As the brightness of the bulbs depend on the voltage across them, connect the bulbs in parallel and the brightness will be the same as one on its own.
2006-11-26 04:21:59 · answer #6 · answered by Kemmy 6 · 1⤊ 0⤋
Yes wiring bulbs in series will decrease the voltage across each successive bulb. They will be quite dim.
2006-11-23 08:57:24 · answer #7 · answered by Edgar Greenberg 5 · 1⤊ 0⤋
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2016-10-12 23:48:38 · answer #8 · answered by ? 4 · 0⤊ 0⤋
either use a dimmer switch or decrease the current that is going to the bulbs by a third maybe..........are they being run in a parrellel circuit or a series circuit.....
2006-11-23 07:16:38 · answer #9 · answered by matthew w 1 · 0⤊ 3⤋
Parallel shares current, series shares voltage - PARALLEL does it for me.
2006-11-24 18:49:22 · answer #10 · answered by lulu 6 · 1⤊ 0⤋