2006-11-23 03:29:25 · 17 answers · asked by astalavista 1 in Science & Mathematics ➔ Mathematics
If 2 pipes take 3h 15min, u should change it to minutes and multiply it by 2 to find the time it takes 1pipe. 3h 15mins= 195 mins
195x2= 390 mins
Then divide by 5 to calculate the time it takes 5 pipes.
390/5= 78 mins
Conversion to hours = 1hour 18mins
2006-11-23 03:39:33 · answer #1 · answered by Just me 5 · 1⤊ 0⤋
If two pipes take 3 hrs 15 min., then five pipes doing the job of two would take 2/5 times as long.
Convert the time to minutes: 180 + 15 = 195.
195*(2/5) = 39*2 = 78.
Convert back to hours: 78 min. = 1 hr 18 min.
2006-11-23 03:43:48 · answer #2 · answered by MathBioMajor 7 · 1⤊ 0⤋
sparkling up for a manner plenty each and each pipe will fill the tank in a million hour: Pipe a million: 4 hrs / a million tank = a million hr / x tank Pipe a million: a million/4 tank in a million hour Pipe 2: 5 hrs / a million tank = a million hr / x tank Pipe 2: a million/5 tank in a million hour as a bring about a million hours' time the tank crammed is the entire of the two pipes abiltiy to fill in a million hour: Pipe a million + Pipe 2 = a million/4 + a million/5 = 9/20 tank crammed in a million hour that's a ratio difficulty of tank/time: (9/20 tank) / a million hour = (a million tank) / x hours the place x = 20/9 hours Simplified to Hours: x = 20/9 = 2.222...hrs Simplified to minutes: 0.22hrs: (0.22hrs)(60min)=13.2min Simplified to Seconds: 0.2min: (0.2min)(60sec)=12sec as a result to fill a million tank utilising Pipe a million and Pipe 2 : answer: 2hrs 13min 12sec
2016-10-12 23:38:06 · answer #3 · answered by ? 4 · 0⤊ 0⤋
195 minutes X 2 pipes/5 pipes = 78 minutes
or 1 h, 18 minutes
2006-11-23 03:43:06 · answer #4 · answered by gregory_s19 3 · 0⤊ 0⤋
2 pipes take 3h +15 mins = 195 mins
Thus for one pipe its 195*2 mins.
And for 5 pipes its (195*2)/5,
so, its 390/5 = 78 min = 1 hour and 18 minutes
I hope this is clear.
2006-11-23 03:40:54 · answer #5 · answered by Paritosh Vasava 3 · 0⤊ 1⤋
I'm assuming that that pipes let in the same amount of water/fluid when running and that they are all started and stopped running at the same time.
The calculations are worked in reverse (it's an inverse ratio).
p - pipe.
2p = 3h 15min. (÷2, x2)
1p = 6h 30min. (x5, ÷5)
5p = 1h 18min.
2006-11-23 03:42:02 · answer #6 · answered by Brenmore 5 · 1⤊ 0⤋
Figure out how much time one pipe would take (twice as much as two pipes).
Then figure out how much time five pipes would take (five times faster than one).
Of course this assumes all the pipes carry the same volume of liquid per minute.
2006-11-23 03:34:05 · answer #7 · answered by Anonymous · 1⤊ 0⤋
It depends on the volume of the pipe and on their fill rate. No one said all the pipes are identical.
2006-11-23 03:54:03 · answer #8 · answered by Edgar Greenberg 5 · 0⤊ 0⤋
2 pipes - 195 seconds
5 pipes - x
so 5 x 195 seconds= 975 / 2 = 487.5 / 60 seconds = 8 hours with 48 minutes.
2006-11-23 03:40:01 · answer #9 · answered by che_karlos 2 · 0⤊ 2⤋
2 pipes 3.25hrs
1pipe 6.5 hrs
5pipes 6.5/5=1.3hrs=1 hr 18 min
2006-11-23 06:05:24 · answer #10 · answered by yupchagee 7 · 0⤊ 0⤋