2006-11-23 02:52:11 · 12 answers · asked by Shorty 1 in Science & Mathematics ➔ Mathematics
INVALID INEQUALITY
3x-12<4 + 3x
12<4 A CONTRADICTION
2006-11-23 02:58:11 · answer #1 · answered by albert 5 · 2⤊ 4⤋
3x-12<4+3x
3x<16+3x
0<16
Infinite Solutions
2006-11-23 03:09:12 · answer #2 · answered by abcde12345 4 · 1⤊ 0⤋
3(x - 4) < 4 + 3x
3x - 12 < 4 + 3x
-12 < 4
X = all real numbers
2006-11-23 02:54:33 · answer #3 · answered by deerdanceofdoom 2 · 3⤊ 0⤋
I suppose it is always true since if yoy develop the left expression
3x - 12< 4+3x this holds for each value of x
2006-11-23 03:05:23 · answer #4 · answered by maussy 7 · 0⤊ 0⤋
3(x - 4) < 4 + 3x --- Multiply the 3 by x - 4
3x - 12 < 4 + 3x --- Subtract 3x from both sides...
-12 < 4
The answer is all real numbers.
Try it out. Put any number you can think of for x ands see if it is true or not...
2006-11-23 02:58:03 · answer #5 · answered by Anonymous · 2⤊ 1⤋
3x-12<4+3x
3x-3x<4+12
0<16 (if we put it in the set all rational numbers greater than 16)
2006-11-23 04:12:54 · answer #6 · answered by sara 2 · 0⤊ 1⤋
3(x - 4) < 4 = 3x
3x - 12 < 4 + 3x
3x - 12 - 3x = 4 + 3x - 3x
0 - 12 < 4
- 12 < 4
- - - - - - - -s-
2006-11-23 03:56:57 · answer #7 · answered by SAMUEL D 7 · 0⤊ 1⤋
3x-12<4+3x
0x-12<4
-12<4
2006-11-23 02:57:39 · answer #8 · answered by Anonymous · 1⤊ 3⤋
3 (x - 4) < 4 + 3x
3x - 12 < 4 + 3x
Cancel out the 3x
You get,
-12 < 4 which is always true.
So 'x' can assume any value.
2006-11-23 03:00:00 · answer #9 · answered by Akilesh - Internet Undertaker 7 · 1⤊ 1⤋
This inequality is invalid for deriving the reduced form of it including x.
2006-11-23 04:00:00 · answer #10 · answered by Paritosh Vasava 3 · 0⤊ 2⤋