How do i solve this?

Question

Three numbers added together total 68. The second number is four more than the first, and the third number is twice the first. FInd the numbers.

How about this one:

11w - 11 = -77

Answer 1

1=16
2=20
3=32

Answer 2

Three numbers added together total 68

First number: n
Second number: n + 4
Third number: 2n
It all equals 68.

n + n+4 + 2n = 68
4n + 4 = 68
4n + 4 - 4 = 68 - 4
4n = 64
n = 16

Going back to our information:

First number=n=16
Second number= n+ 4, so 16+4=20
Third number = 2n, so 2 * 16= 32
Then check: 16+20 +32=68


Terra did the whole process correctly for the following, but I think she had a typo at the end:

11w - 11 = -77

11w - 11 + 11 = -77 +11
11w = -66

Divide each side by 11

w= -6 (not -66)

Answer 3

Okay, I will tell you the answers, but I will explain how I got them so you know.
1) lets call the first number A.
first number=A
2 number=A*4
3 number = A *2. now set up the equation.
A+A*4+A*=68.
Solve for A
A is the first number
now do A*4 thats the second number
A*2=third number


1=16
2=20
3=32


2)11w - 11 = -77
an equation is like a scale. If you do something to one side you must do it to the other. In this equation you want to have only the w on one side and a number on the other side of the =. To do this you need to get rid of numbers on the left side. First lets get rid of the -11. In order to get rid of the -11, you need to add 11. which gives you zero. But remember, if you add 11 to one side you need to add it to the other.
11w-11=-77
+11 +11
you know have
11w=-66
now you need to get rid of the 11. because the 11 is suppoused to be multiplied by the w, you need to do the opposite and divide.
11w=-66
/11 /11
so you get.
w=-66

Answer 4

Try this where x = the first number.

68=x + x+4 + 2x

68=4x + 4

64=4x

x=16

numbers: 16, 16+4 and 16 x 2

numbers: 16, 20 and 32

Answer 5

x+(x+4)+(2*x)=64