pls translate the meaning into English.thanks!
2006-11-22 01:12:50 · 12 answers · asked by Anonymous in Society & Culture ➔ Languages
♡Yes, that's right.
'Hajimemashite' means:
★hajimemashite ( 始めまして : はじめまして )
～ha-gee-meh-mah-she-teh
1. How do you do? (id)
2. Nice to meet you (id)
You can check it here as well:
http://www.yesjapan.com/dictionary/yesjapan200k.php?language=Japanese&searchplace=beginning&searchfor=hajimemashite&maxsearch=25
Hope this helps!♡
2006-11-22 02:25:28 · answer #1 · answered by C 7 · 7⤊ 0⤋
Hajimemashite means "nice to meet you." It's literally something along the lines of "this is the first time" as in the first time meeting someone.
It's usually followed with "Dozo yoroshiku onegaishimasu" which doesn't have an English translation, and is difficult to approximate, but means something like "please treat me well" or "let's have a good relationship." Really hard to translate...
2006-11-22 02:29:04 · answer #2 · answered by Willow Wisp 2 · 3⤊ 0⤋
Hajimemashite
2016-09-28 09:44:42 · answer #3 · answered by clawson 4 · 0⤊ 0⤋
Roughly translated "how do you do?"it's basically the title to a japanese anime.
2006-11-22 01:21:39 · answer #4 · answered by skanken808 2 · 0⤊ 0⤋
Pleased to meet you. It is a formal level of politeness, but not the most formal level. :) There are three levels of politeness (casual, formal, utmost respect and honor).
2006-11-22 01:27:36 · answer #5 · answered by Anonymous · 0⤊ 0⤋
http://animeworld.com/japanese/lesson2-2.html
2006-11-22 01:16:33 · answer #6 · answered by penningtonuk2000 3 · 0⤊ 0⤋
I think that it's "nice to meet you" or something along those lines.
2006-11-22 01:14:54 · answer #7 · answered by Dmitri 3 · 1⤊ 0⤋
Hajimimashite..! Watashi wa Funkysuze!
How do you do, my name is funkysuze!
2006-11-22 01:44:19 · answer #8 · answered by funkysuze 3 · 0⤊ 0⤋
"Pleased to meet you."
It's a polite phrase to use when introducing yourself.
2006-11-22 01:42:08 · answer #9 · answered by evilspikeagon 2 · 0⤊ 0⤋
Yep, it's 'Nice to meet you'
2006-11-22 03:09:27 · answer #10 · answered by esther c 4 · 0⤊ 0⤋