1. How to solve for n when 3^n + 4^n = 25?
2. Using this, can we solve Q for
50 = 1/ [(2(Q-1)^-n) + (2(Q+1)^-n) +(2Q^-n)]?
2006-11-21 17:43:56 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Engineering
i believe it's gonna be more than just observing the answer for n = 2 for Q1. Can prove by using logarithm?
2006-11-22 01:33:33 · update #1
1. if you have a TI83/84, then put
y1=3^x+4^x
y2=25
where they intersect is the answer
2. do the same thing, put one side of the equation as y1 and the other side as y2
this is much faster than using logs!
2006-11-21 17:49:31 · answer #1 · answered by a 4 · 1⤊ 0⤋
in first Q we will take observation and so that n = 2. and then put n=2 in 2nd Q . one unknown and one equ. so that we can solve.
otherwise if you get any other solution then please tell me.
2006-11-22 01:56:05 · answer #2 · answered by jitendra vishnoi 1 · 0⤊ 0⤋
nlog3 +nlog4=25
n(log3+log4)=25
n=......
2006-11-22 02:27:12 · answer #3 · answered by T- capricorn 2 · 0⤊ 0⤋