Father: I see in your answers that you are married and you are a catholic priest, I also see that you are a priest of course. Please tell me are you a priest of the Anglican use, the dispensation that John Paul II gave to those from the Anglican church wanting to be in full communion with the holy see? You know what i am talking about? Would you care to explain please? thank you and God bless.
2006-11-21 04:37:13 · 5 answers · asked by Dominicanus 4 in Society & Culture ➔ Religion & Spirituality
Thank you father, I pray trustilly to God too for that day too. God bles you and all our Anglican brethren. many Catholics of the Roman rite are really waiting and hoping for the day, i am one. God bless
2006-11-21 04:48:59 · update #1
I live in Texas and here there are a lot of the anglican use, i have been to one of them
2006-11-21 04:50:33 · update #2
Hmmm,
I am not a Priest, but there are some Roman Catholic Priests that are married.
They were married before converting to Catholicism.
Peace!
2006-11-21 04:41:41 · answer #1 · answered by C 7 · 0⤊ 0⤋
No. We tried to get into the Anglican Use/Pastoral Provision back in the 1980's when Cardinal Law was in charge of it. But then-Archbishop Mahony wouldn't let us in - as we would have been in his Archdiocese.
I am a Traditional Anglican....we broke off from the Episcopal Church when they made the first "priestesses" back in 1976.
We are the Traditional Anglican Communion - Archbishop John Hepworth. Do a Google search on both of those....
We are currently making progress toward some kind of intercommunion with the Vatican - I pray for success daily.
See:
2006-11-21 12:45:13 · answer #2 · answered by Anonymous · 1⤊ 0⤋
yeah, come on Father K spill the beans.
2006-11-21 12:44:10 · answer #3 · answered by Sentinel 7 · 0⤊ 0⤋
yeah... like i saw father k also. He is so bad.... i don't think he is a priest.
then again i do, all catholic priest are like so weird
2006-11-21 12:46:32 · answer #4 · answered by Anonymous · 0⤊ 2⤋
huh?
2006-11-21 12:40:11 · answer #5 · answered by sweetsum691 5 · 0⤊ 0⤋