2006-11-20 07:45:47 · 5 answers · asked by RBJ 2 in Science & Mathematics ➔ Engineering
The only situation there is for placing a trap at the far end of an antenna, is if that antenna is part of a multi-band antenna system. For instance, you could put a trap at the end of a 1/4 wave 20m antenna (at about 16 ft), then connect the other side of it to an additional element, for 40m or 80m use. If the antenna is for 160m, the only reason to have an extension is for BCB or LW coverage. Is that what you're up to? By the way, as already mentioned, the trap has to be used at a current peak (voltage node).
2006-11-20 10:00:48 · answer #1 · answered by pack_rat2 3 · 1⤊ 1⤋
Assuming you are talking about an antenna system for 160 meter band, and you are talking about placing a trap made out of coax at the end of the antenna wire....
The answer is NO.
Trap works by acting as a switch that opens up at the resonance frequency. If you place it at the far end of the antenna wire, there is nothing to cut off. So it has no effect.
Any loading coil in the antenna system must be placed at the point there are some current. Placing it at the far end (which is voltage maxima and current minima) has no effect. This is another reason why it won't work.
Next time, please define your question clearly.
2006-11-20 16:07:57 · answer #2 · answered by tkquestion 7 · 1⤊ 1⤋
Are you talking about a Coaxial Trap to filter out unwanted data? Coax traps are usually used to filter out unwated information on a coax line. They usually use such devices to filter out Television from a line is someone is only subscribing to Data/Telephony. There's no real reason to use such a device unless you are trying to filter out said traffic. All of my information is concerning Cable Internet, Television, and Phone. If you are talking about some other trap then I am not sure.
These videos describe cable traps:
https://www.youtube.com/watch?v=AJs10qoMFCc
https://www.youtube.com/watch?v=cd7HnfxPKjM
Attaching this video so you can learn more about Coaxial Cables:
https://www.youtube.com/watch?v=2Ew_qX3AHxA
2013-10-15 19:32:49 · answer #3 · answered by James 1 · 0⤊ 0⤋
dont understand the question
2006-11-20 15:59:13 · answer #4 · answered by bob h 2 · 0⤊ 1⤋
What are you talking about?
2006-11-20 15:49:36 · answer #5 · answered by ? 3 · 0⤊ 1⤋