How much energy is required to boil water when the water is initially 25 C.
2006-11-19 19:59:20 · 4 answers · asked by Cash 1 in Science & Mathematics ➔ Physics
mcdelta theta
m=1 kg(by default)
c=4.2 J/degree/kg
delta theta= 75
e=1*75*4.2
=315 j
2006-11-19 20:32:38 · answer #1 · answered by anuragmaken 3 · 0⤊ 0⤋
Assuming that we boil water on place near the surface of the earth then the energy (in the form heat) Q needed may be calculated using the formula
Q=m*c*dTheta
where m is the mass of water (in kg)
c is a constant depending on the substance being heated
dTheta is the difference in temperature. In order to boil water, where Theta(final)=100, starting from Theta(initial)=25, we have dTheta=75.
2006-11-20 04:10:31 · answer #2 · answered by fanis t 2 · 0⤊ 0⤋
this would depend on the mass of water say for example the mass of water used is 4kg,boling poiunt temp of water=100*C below sea level(at normal conditions)
Q=mCPdeltaT
Q= (4kg)(4.187J/kgK)(373K-298K)
Q=1256.1J=1.2561KJ
2006-11-20 04:40:36 · answer #3 · answered by cedric chad l 1 · 0⤊ 0⤋
at what pressure?
2006-11-20 04:09:17 · answer #4 · answered by Jesters Deadd 2 · 0⤊ 0⤋