If this is a fraction in two variables, which it appears to be, then it's quite simple. A single variable, multiple variables, or an expression containing variables raised to a negative power, -n, can be re-written as 1 divided by the variable, multiple variables, or expression. So x^-4 becomes 1/ x^4; (a+b)^-2 becomes 1/(a+b)^2; 2(xy)^-1 becomes 2/(xy), etc. In this particular example, if we re-write this, we get x^2/y^-3 = x^2/ (1/y^3) = (x^2)*(y^3/1) = x^2*y^3. We invert and multiply the numerator by the denominator because it (the denominator) has now become a fraction, and the rules of mathematics governing division by a fraction demands that this be done, otherwise the result is incorrect. You can demonstrate this to yourself by converting fractional denominators to decimal form and then performing the division.
You may also want to review the laws of exponents.
2006-11-19 18:45:27
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answer #1
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answered by MathBioMajor 7
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x^2 2 already is a positive exponent
y^-3 Any negative exponent can be written as a postive exponent by taking the reciprocal of the term. That is y^-3 = 1/y^3
2006-11-19 18:09:14
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answer #2
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answered by B.O. 2
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...A damaging exponent only skill which you're dividing by utilising that type after elevating it to the capability. So only circulate that area to the denominator, and it will become a good exponent. 40 two x^11 y^-5 = 42x^11 / y^5
2016-11-25 20:47:41
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answer #3
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answered by Anonymous
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To change an expression with a negative exponent to a positve one, put it in the denominator.
In x^2, the exponent is already positive
In y^-3, chang it to 1/y^3
2006-11-19 18:10:27
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answer #4
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answered by jharr412 2
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1 / y^ -3 = y^3 and vice versa. the easy way to think of it is just switch it from the denominator to the numerator. if x had been to a negative power you'd switch it to the denominator.
final answer: x^2 y^3
2006-11-19 18:08:30
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answer #5
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answered by nctropia 2
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The answer is simple y^-3 is equivalent to 1/(y^3). so,
X^2 x^2
------ = -------- = (x^2)*(y^3)
Y^-3 (1/y^3)
2006-11-19 18:13:09
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answer #6
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answered by d_astro 2
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x^2/y^-3=x^2y^3
2006-11-19 18:19:45
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answer #7
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answered by yupchagee 7
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