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Consider the following half-reactions and E0 values:

Ag+(aq) + e- --> Ag(s) E0 = 0.80 V
Cu2+(aq) + 2 e- --> Cu(s) E0 = 0.34 V
Pb2+(aq) + 2 e- --> E0 = -0.13 V

a/ Which of these metals or ions is the strongest oxidizing agent? Which is the strongest reducing agent?

b/ The half-reaction can be used to construct three different galvanic cells. Tell which cell delivers the higest voltage.

c/ Write the cell reaction for par (b) and calculate the values of E0, ΔG0 (in kilojoules), and K for this reaction.

d/ Calculate the voltage for the cell in part (b) if both ion concentration are 0.010M

2006-11-19 17:21:59 · 3 answers · asked by Kriztine96 1 in Science & Mathematics Chemistry

3 answers

I'll start you on your way.
Ag+ is the strongest oxidising agent, because it has the most positive E value. Pb metal is the strongest reducing agent because it has the most negative E value.
So combining those two into a cell will give the largest voltage difference.
The equation will be Pb + 2Ag+ ---> 2Ag + Pb2+

Now you can do the calculations.

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