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The half-life of a drug in the bloodstream is 4 hours. By what factor does the concentration of the drug decrease in 24 hours? in 36 hours?

2006-11-19 15:10:25 · 3 answers · asked by RITA 1 in Science & Mathematics Mathematics

3 answers

1/2=e^-4k
-ln2=-4k
k=ln 2 /4=0.1732868
C/Co=e^-.1732868t
24 hrs C/Co=.015625
36 hours C/Co=0.001953125

You could do the by saying that 24*4*6 so after 24 hrs
C/Co=.5^6=.015625
& 36=4*9 so after 36 hrs
C/Co=.5^9=.001953125
Much easier but only works for t=4n where N is an integer

2006-11-19 15:34:32 · answer #1 · answered by yupchagee 7 · 16 0

F = 1 / ( 2^(t/4) )

2006-11-19 23:57:22 · answer #2 · answered by hznfrst 6 · 0 0

24 hours = 6 half lives = 2^(-6) = 1/64
36 hours = 9 half lives = 2^(-9) = 1/512

now multiply it by original drug concetration and compare to drug test threshold.

2006-11-19 23:13:19 · answer #3 · answered by Anonymous · 0 0

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