2006-11-19 14:17:46 · 10 answers · asked by wanda_brown62 1 in Science & Mathematics ➔ Mathematics
(x+2)/(x+2)(x+3)=
1/x+3
2006-11-19 14:20:15 · answer #1 · answered by Anonymous · 4⤊ 0⤋
x+2 divided by x^2+5x+6
= (x+2) /(x^2+5x+6)
= (x+2) /(x+3)(x+2)
=1 /(x+3)
Thats the answer
2006-11-20 09:46:41 · answer #2 · answered by Paritosh Vasava 3 · 1⤊ 0⤋
x+2 / x^2+5x+6 x+2 / (x+2)(x+3) 1 /(x+3)
2006-11-20 05:36:43 · answer #3 · answered by sam 3 · 1⤊ 0⤋
1 /(x + 3)
X^2 + 5x + 6 = (x+2) (x+3)
2006-11-19 22:26:13 · answer #4 · answered by MrWiz 4 · 2⤊ 0⤋
(x + 2)/(x^2 + 5x + 6) = (x + 2)/((x + 3)(x + 2)) = 1/(x + 3)
2006-11-20 01:09:44 · answer #5 · answered by Sherman81 6 · 1⤊ 0⤋
1 / (x+3)
2006-11-19 22:19:40 · answer #6 · answered by Anonymous · 2⤊ 0⤋
one over x +3. you gotta take the denominator apart- simplify it, if you will. so what times what adds to get five and multiplies to get six? that would be 3 and 2, both positive. so, in the denominator, go (x+3) (x+2). so you have x+2 over (x+2)(x+3). x+2 divides out so you have one in the numerator and x+3 in the denominator. you probably don't care, but i'm learning the same thing and it helps me learn when I explain it to other people.
2006-11-19 22:28:45 · answer #7 · answered by keep it real 4 · 2⤊ 0⤋
(x+2)/(x^2+5x+6)
(x+2)/((x+3)(x+2))
1/(x+3)
2006-11-19 23:05:23 · answer #8 · answered by yupchagee 7 · 1⤊ 0⤋
1/(x+3)
Algebra
2006-11-19 22:29:10 · answer #9 · answered by money4lyfe 2 · 2⤊ 0⤋
I don't know
2006-11-19 22:25:31 · answer #10 · answered by Unknown Artist~ 4 · 0⤊ 2⤋