Find two numbers for which the principal square root of the number is the same as the number.. Plz help. Thanks.
2006-11-19 14:06:57 · 6 answers · asked by ?? 1 in Science & Mathematics ➔ Mathematics
Let x represent the numbers
Then x^2 = x
So x^2 - x = 0
x(x - 1) = 0
x = 0, 1
2006-11-19 14:52:34 · answer #1 · answered by Wal C 6 · 0⤊ 0⤋
â1=1
â0=0
2006-11-19 22:12:30 · answer #2 · answered by yupchagee 7 · 0⤊ 0⤋
1 and 0
2006-11-19 22:09:03 · answer #3 · answered by sexy_felix_is_here 2 · 0⤊ 0⤋
1*1 = 1
0*0 = 0
1 and 0 are your square numbers
2006-11-21 02:52:53 · answer #4 · answered by Akilesh - Internet Undertaker 7 · 0⤊ 0⤋
powers are the result when a number multiplies itself. It's asking for two numbers that equals itself when multiplied by itself. Get it?
2006-11-19 22:09:57 · answer #5 · answered by ny 3 · 0⤊ 0⤋
Zero and one.
2006-11-19 22:10:12 · answer #6 · answered by Mark S, JPAA 7 · 0⤊ 0⤋