x intercept of the function?

Question

I am having a hard time trying to find the x-intercept of the function
y= -1/3 (x^3-3x+2)
i set y to zero and try solving for x but i cnt do it!!
how do i solve for the x intercept (what is it?!?!?))
ive been trying to figure out this problem for ever!!!!!!
i hve to find asymptotes, intercepts, relative min and max, concave up and down and all that jazz...
so annoying!
any help is GREATLY appreciated!!! tHANK YOU!!!!

if i graph it, it intercepts the x axis at -0.596, i just have no idea how to get that. i already solved for it by plugging in zero for y and solving for x, but it just got me to a cube and x.
gr. this is so annoying!

ok so when i graph it i get the x intercepts at (-2,0), (1,0).
what the heck!! how???

Answer 1

Tip: If the sum of the coefficients of the polynom are zero, then x =1 is a zero of the polynom.

x = 1
If you need more roots do the synthetic divisiona and then use the quadratic formula.

Answer 2

You can't find an intercept because one does not exist.

There are asymptotes where the bottom is equal to zero and when x gets large (either positive or negative)

Answer 3

to solve for x intercept, set x to zero and solve for y