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The formula for distance traveled under constant acceleration a is s=.5*a*t^2. The general formula is a(t) = d^2 x(t) /dt^2, acceleration is the second derivative of position (distance) with respect to time.

2006-11-19 13:49:06 · answer #1 · answered by gp4rts 7 · 0 0

Acceleration is the time rate of change of velocity, and distance is the time rate of change of velocity.

In deriviatve equation form acceleration is defined as follows:

dv/dt = a

Integrating we get:

v = at + c where c is a constant and represents the initial velocity.

Now distance s = the integral of velocity with respect ot time

ds/dt = at + c

Integrating s = ct +(-) 1/2at^2 which is the equation for distance where c is the intial velocity. The +- means the accelleration can be in any direction, forward backward, up or down

2006-11-19 22:07:17 · answer #2 · answered by wealthmaster 3 · 0 0

distance divided by time twice is acceleration. The acceleration is the double integral of position. The position is the double derivative of the acceleration.

2006-11-19 21:45:52 · answer #3 · answered by Christine 1 · 0 1

the more you accelerate, the more distance you cover in a quicker amount of time.

2006-11-19 21:44:48 · answer #4 · answered by L 4 · 0 0

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