Methanol, CH3OH, can be made by combining gaseous carbon monoxide and hydrogen gas.?

Question

Methanol, CH3OH, can be made by combining gaseous carbon monoxide and hydrogen gas.
In one experiment 1.40 g of H2 is mixed with 13.85 g of CO.


What is the theoretical yield of CH3OH ? I.E., how many grams of CH3OH should be formed?

Enter a numeric answer only, no units.

Thanks for explaining it to me :)

Answer 1

In the presence of the proper catalyst:

CO + 2 H2 --> CH3OH

1.40 g of H2 = 1.40 g / 2.016 g/mol = 0.694 moles H2

13.85 g CO = 13.85 g / 28.01 g/mol = 0.4945 moles of CO

It takes 2 mole of H2 for every 1 mole of CO, so only 0.347 moles of CO will react. This will give 0.347 moles of CH3OH:

32.04 g/mol * 0.347 moles = 11.12 grams

11.12 is your answer.

Answer 2

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