Please show me the equation for this???
2006-11-19 11:38:23 · 15 answers · asked by Dee Dee 1 in Science & Mathematics ➔ Mathematics
1 in 8
2006-11-19 11:40:22 · answer #1 · answered by Jimbo 2 · 0⤊ 1⤋
There are 2 opportunities, heads or tails, for each toss. to discover an gathered threat, you ought to multiply the three possibilities mutually. Your question isn't real sparkling. in case you recommend you may have #a million head #2 tails #3 heads, then this can be the answer: First toss = a million/2 2nd toss = a million/2 0.33 toss = a million/2 a million/2 * a million/2 * a million/2 = a million/8 ---------------------------------------... in case you recommend it may start up with the two heads or tails and then exchange, it is the answer: a million/8 may be the answer if heads is first a million/8 may be the answer if then tails is first So, you ought to upload the two opportunities a million/8 + a million/8 = 2/8 = a million/4 ----------------------------------- people have been giving me a thumbs down without thinking of the variable solutions reckoning on what your difficulty relatively exchange into asking.
2016-10-22 09:28:30 · answer #2 · answered by bergene 4 · 0⤊ 0⤋
If a coin is tossed 3 times....
the first time it was tossed you have 2 possibilities. (heads or tails)
the second time, you also have 2 possibilities
the 3rd time you also have 2 possibilities..
total combination:
2*2*2=8
so there would be an 1/8 chance you could get heads heads tails
2006-11-19 11:43:40 · answer #3 · answered by Anonymous · 1⤊ 1⤋
There are 8 [that's 2^3] possible outcomes.
HHH
HHT
HTH
HTT
THH
THT
TTH
TTT.
Your HHT is just one of the eight, so P = 1/8.
A different question would be probability of 2 heads, 1 tail (and order doesn't matter). In that case, P = 3/8
2006-11-19 11:56:37 · answer #4 · answered by Philo 7 · 0⤊ 1⤋
Easy. You have three flips. For each flip, there is a 50/50 chance of either side. Set it up like this:
1/2 * 1/2 *1/2= 1/8
Based on this, you have a one in eight shot of getting heads, heads, tails.
2006-11-19 11:41:19 · answer #5 · answered by Rckets 7 · 1⤊ 1⤋
Multiply the odds for each toss.
1/2 * 1/2 * 1/2 = 1/8
2006-11-19 11:42:27 · answer #6 · answered by Barkley Hound 7 · 2⤊ 1⤋
If it needs to be in that sequence:
assuming that each side has a probability of 50% (=0.5)
0.5 * 0.5 * 0.5 = 0.125 = 1/8
If it is just 2 times heads and one time tail:
Number of possibilities = 8 (2 * 2 * 2)
Number of matches: 3 (h + h + t / h + t + h / t + h + h)
=> 3/8 = 0.375
2006-11-19 11:41:23 · answer #7 · answered by markus0032003 4 · 0⤊ 1⤋
1 in 3.
2006-11-19 11:39:36 · answer #8 · answered by soulguy85 6 · 0⤊ 4⤋
umm its 1/8 cuz the chance of heads verse tails per toss is .5 so three tosses means .5 x .5x .5= 1/8
also you can look at all the possible combinations:
hhh, ttt, hht, htt, hth.....ect...and ull get get that any combo with 2 heads and one tail shows up 1/8 of the time
Hope that helps :/
2006-11-19 11:41:11 · answer #9 · answered by as 4 · 1⤊ 2⤋
1. prob. of getting heads on first toss 1/2
2. prob. of getting heads on 2nd toss 1/2
3. prob. of getting heads on 3rd toss 1/2
1/2 x 1/2 x 1/2 = 1/8
2006-11-19 11:41:43 · answer #10 · answered by J3Buckets 2 · 1⤊ 2⤋