if you subtract a number from 4 times its square the result will be 3?

Question

i am not sure how to do it i need to factor
Is this how i start
(4*x^2)-x=3
If this is it i am not sure how to factor it

Answer 1

4x² -x = 3
4x² - x - 3 = 0
(4x + 3)(x - 1) = 0
x = -3/4, x = 1

Answer 2

Yes that is it and you do need to factor, but you must make it equal to zero first:

4x^2 - x - 3 = 0

FOIL: (4x + 3)(x - 1) = 0

So the answers are x = 1 or x = -3/4

Answer 3

4x^2 - x = 3 4x^2 - x - 3 = 0 utilising the quadratic formula: x = {-b +/- sq.(b^2 - 4ac)}/2a x = [a million +/- sq.(a million - 4(4)(-3))]/2(4) x = [a million +/- sq.(40 9)]/8 x = [a million +/- 7]/8 x = -3/4, a million - .--

Answer 4

change to

4x² - x - 3 = 0

then move it to (ax+b)(cx+d)=0 format

i'd guess (but i'm drunk)

(4x +3)(x -1)=0

so x = 1
or x = - 3/4

Answer 5

i think it is (4-x)^2=3 i just finished doing this in math. good luck