A man of mass 80 kg sits in a chair. What it the magnitude of the normal force exerted on the man by the?

Question

Chair??

1)70.2 N
2)80 N
3)89.8 N
4)784 N

Please Help!!

Answer 1

The answer is 4)

The reason for this is that when the man sits in the chair, he's not accelerating. That means that the net force on him is 0 N. In other wrads, the normal force the chair exerts on the man must equal the man's weight:

N = W

The man's weight is simply his mass times the gravitational acceleration (g = 9.8 m/s²):

W = m * g

Therefore:

N = W = m * g

N = (80 kg)(9.8 m/s²)

N = 784 Newtons

Hope that clears things up a bit! :)

Answer 2

The man's weight is 784 N (W = m*g). A body in equilibrium has zero net force acting on him. His weight is a force. The chair provides an equal and opposite force of 784 N.

Answer 3

The answer is number 4 (784 N)

Force = Mass x Gravity
We know that Gravity is 9.81m/s^2
Hence:
Force = 80 x 9.81 = 784 N

Answer 4

80 kg x 9.8 m/s^2 = 784 kg m/s^2 = 784 N

Answer 5

a) You in certainty choose for to locate his weight. it extremely is the stress that gravity will exert on him to maintain him in the international, so may be the comparable stress that he will stick to to the chair. Mass x gravitational container capability = weight in the international the gravitational container capability is approximately 9.82N/Kg So 70x9.eighty two = 687.4 Newtons. b) for each action there is an equivalent and opposite reaction. So this suggests the stress that launches him upwards may be the comparable stress that he will exert on the chair. stress = mass x acceleration 70 x7.2 =504 Newtons

Answer 6

The normal force is opposite of the gravitational force (weight).

W=mg
=(80kg)(-9.8)=-784N

Normal force is then 784 N.

Answer 7

to find the normal force, multyply its mass by the acceleration of gravity. 80 times 9.8 and that gives you ur normal force.