(6x^3+7x^2-x+26)/(x-3)?

0 ⤊

(6x^3+7x^2-x+26)/(x-3)?

solve by synthetic division

2006-11-19 10:45:28 · 3 answers · asked by Kirk T 1 in Science & Mathematics ➔ Mathematics

3 answers

6x^2-11x-32 R122

2006-11-19 10:56:28 · answer #1 · answered by Julia 4 · 0⤊ 0⤋

(6x^3 + 7x^2 - x + 26) / (x-3)
first term is 6x^2
remainder is 7x^2 - 3(6x^2) - x + 26
or -11x^2 - x +26
second term is -11x
remainder is -x -3(-11x) +26
or 32x + 26
third term is 32
remainder is +26 - 96 = -70
So answer is 6x^2-11x+32 -70/(x-3)

2006-11-19 10:52:12 · answer #2 · answered by Steve A 7 · 0⤊ 0⤋

6x^2-11x-34-(76/(x-3))

2006-11-19 10:53:11 · answer #3 · answered by ferrari5107 2 · 0⤊ 0⤋