Science help please?

Question

A type of elevator called a cage is used to raise and lower miners in a mine shaft. Suppose the cage carries a group of miners down the shaft. If the unblanced force on the cage is 60.0 N, and the mass of the loaded cage is 1.50*10^2 kg, what is the acceleration on the cage?

Answer 1

F=ma
force =mass*acceleration
60.0 N= 1.50*10^2 Kg (a)
60.0N/1.50*10^2 Kg =a
a=4000 m/s^2

Answer 2

F=ma 60=1.5 x10^2 60=150a 60/150=a a=.4m/s