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1/s'=(1/f)-(1-s)

what would s' be.

i thought you would just have to invert each one and get s'=f-s but that is not the case.

2006-11-19 10:14:16 · 2 answers · asked by ElDarado05 2 in Science & Mathematics Physics

spherical mirror equation

2006-11-19 10:16:46 · update #1

2 answers

aka the lens formula, I think you mean 1/s'=1/f-1/s where, unless there are parenthesis to tell you what to do first, division is done before subtraction. Your answer violates the rules of algebra. To invert both sides you get:
s'=1/(1/f-1/s) which is a compound fraction. To make a simple fraction, multiply by 1=fs/(fs). You then get:
s'=fs/(s-f)

2006-11-19 10:59:59 · answer #1 · answered by Dr. R 7 · 1 0

s' = 1/((1/f)-(1-s))

You can't split the 1/f and 1-s bits. There's not much else you can do to simplify it, but it could also be written

s' = 1/(1/f-1+s)

2006-11-19 18:51:15 · answer #2 · answered by Jimbo 2 · 0 0

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