what is the solution set for 2x^2-7x-4=0
steps would be helpful and much appreciated.
2006-11-19 10:11:03 · 4 answers · asked by BLUEEEE 1 in Science & Mathematics ➔ Mathematics
1.factor
(2x+1)(x-4)=0
2.set it to 0
2x+1=0
or
x-4=0
3.solve
{x=-1/2 or x=4} <=answer
2006-11-19 10:24:09 · answer #1 · answered by ming 2 · 0⤊ 0⤋
Factor the equation to get
(x - 4)(2x + 1)=0
By the zero product property, x = 4 or x = -.5
2006-11-19 18:13:34 · answer #2 · answered by Texas Cowgirl 3 · 0⤊ 0⤋
the equation can be factored into (2x+1)(x-4) (if you didn't have a clue how to factor it, use the quadratic formula).
(2x+1)(x-4)=0
x=4, -1/2
2006-11-19 18:14:52 · answer #3 · answered by Ramesh S 2 · 0⤊ 0⤋
first you have to break it up and factor it using foil
(2x+1) (x-4)
then you do them seperately
2x+1 = 0
-1 -1
2x= -1
x= -1/2
( x - 4 ) = 0
x= -4
so x = -1/2 or -4
2006-11-19 18:17:04 · answer #4 · answered by jenn123456 2 · 0⤊ 0⤋