What is the Kp for this equation?

Question

Question Details:CO2(g) + H2(g) ↔ H2O(g) + CO(g) When H2(g) is mixed with CO2(g) at 2,000 K, equilib­rium is achieved according to the equation above. [CO] = 0.385 M [H2O] = 0.385 M [H2] = 0.365 M [CO2] = 0.465 M And if it helps Kc = 0.87

Answer 1

here, you just use the ideal gas law, PV=nRT. since molarity is equal to moles of solute per liters of solution, M=n/V, so P=MRT.
therefore,
Kp=Pco*Ph2o/(Ph2*Pco2)
=[CO]RT*[H2O]RT/ ([H2]RT*[CO2]RT)
all the RT coefficients end up canceling out, so:
Kp=[CO][H2O]/[H2][CO2]
=Kc
since there were equal numbers of gas molecules on each side of the equation, Kp was equal to Kc. as a general rule, Kp=Kc*(RT)^N, where N is the change in the number of gas molecules.

Answer 2

The relationship between Kc and Kp is hard to type with our limited formatting.

From the balanced equation and figure out the change in the number of moles of gaseous substances I'll call this "delta n"

Kp = Kc(RT)^delta n (raise the quantity "RT" to the power of whatever delta n was.)

In your equation the change in the number of moles of gas is 0 (1 mole of CO2 + 1 mole of H2 = 1 mole of H20 + 1 mole of CO.)

Therefore, Kc = Kp

Use the reactants/products expression for any equilibrium constant to calculate Kc which will = Kp

0.385 x 0.385 divided by 0.465 x 0.365 = 0.873

As a note for the future: if "delta n" is NOT 0, the "R" in the "RT expression is 0.08206 Liter-atm/mole-K. The "T" is the temperature on the Kelvin scale.

Answer 3

Kp Formula

Answer 4

thank you