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A 2.50 102-N force is pulling an 90.0-kg refrigerator across a horizontal surface. The force acts at an angle of 15.0° above the surface. The coefficient of kinetic friction is 0.200, and the refrigerator moves a distance of 5.00 m. Find

(b) the work done by the kinetic frictional force.

2006-11-19 09:00:41 · 1 answers · asked by Anonymous in Science & Mathematics Physics

A 2.50 E2-N force is pulling an 90.0-kg refrigerator across a horizontal surface. The force acts at an angle of 15.0° above the surface. The coefficient of kinetic friction is 0.200, and the refrigerator moves a distance of 5.00 m. Find

2006-11-19 09:01:26 · update #1

1 answers

work = f*d
so we just need the force since we know d=5

the vertical force on the surface is:
mg-sin(15)*250
=90*9.8-sin(15)*250
to compute the frictional force, multiply by the coefficient of friction
and by the distance for the work
F=5*.2*(90*9.8-sin(15)*250)
=817.3



j

2006-11-19 09:17:13 · answer #1 · answered by odu83 7 · 0 0

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