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Ive been working on this all day, and seriously need some help!

Three masses are connected together by strings. Starting from left and going right, mass 1 is 12kg, mass 2 is 24kg, and mass 3 is 31kg. The force applied to the string attached to mass 3 and is pulling right is 65N. (a) Find the acceleration of the system (b) find the tension in the string between mass 1 and mass 2 (c) between mass 3 and mass 2. Assume no friction

2006-11-19 08:56:05 · 3 answers · asked by sur2124 4 in Science & Mathematics Physics

3 answers

The acceleration of the system can be found using F=ma
or a=F/m
a=65/(12+24+31)
=.97 m/s^2

for the tensions, use the same equation considering the forces on each string.

for m1 the force is what is pulling the mass so that it accelerates at .97m/s^2
F=12*.97
=11.64 N

for the string between m2 and m3
F=(12+24)*.97
=34.92

j

2006-11-19 09:02:15 · answer #1 · answered by odu83 7 · 0 0

Easiest way is this:

F = ma = (12 + 24 + 31)a

You know F, so you can get a.

Now you know a, you can calculate the force in the strings.
For mass 1 to 2, the mass being pulled is 12 kg, so F = 12a.
For mass 2 to 3 the mass being pulled is 12 + 24kg, so F = 26a

2006-11-19 09:06:44 · answer #2 · answered by Anonymous · 0 0

the galaxies rotate at speeds inconsistent with their obvious mass is by technique of the fact we do see all of it. i'm bearing on it as being the theoretical darkish count number. There are very reliable proofs that shows that darkish count number exist. One the is the inconsistent speed of and obvious mass. darkish count number makes up approximately seventy 5% to eighty% of the problem contained in the Universe...

2016-10-04 03:40:41 · answer #3 · answered by Anonymous · 0 0

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