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the question is:
in its approach to an airport ruway, an airplane of mass 1.24x10^5 kg has a velocity of 75.5 m/s [11.1 degrees below the horizontal] determine the horizontal and vertical components of its momentum

2006-11-19 07:43:00 · 3 answers · asked by M.K 2 in Science & Mathematics Physics

3 answers

Find the horizontal and vertical components of its velocity. (Hint: one is v*sin(ø) and the other is v*cos(ø).) Each velocity times the ariplane's mass is that direction's component of momentum.

2006-11-19 07:53:08 · answer #1 · answered by gp4rts 7 · 2 0

Use trigonometry.
Sin = Opposite/Hypotenuse
Cos = Adjacent/Hypotenuse

Hypotenuse = scalar momentum
Opposite = vertical component
Adjacent = horizontal component

The angle is given. Just multiply the trig function results by the scalar momentum and voila!

2006-11-19 07:53:12 · answer #2 · answered by DJL2 3 · 2 0

1

2017-02-28 00:12:51 · answer #3 · answered by ? 3 · 0 0

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