does anyone know the domain for f(x)=1/3(x+2)^2-12?

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does anyone know the domain for f(x)=1/3(x+2)^2-12?

thankyou

2006-11-19 07:20:15 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

3 answers

Do you mean the range? The domain is usually specified. In this case it would probably be all the real numbers.

As for the range, it can get as large as it it want, if we keep increasing the size of (x+2)^2. The lowest value would be when (x+2)^2 = 0 as this is the lowest this term can get. So the range is all numbers greater than or equal to -12.

2006-11-19 07:27:50 · answer #1 · answered by coolman9999uk 2 · 0⤊ 0⤋

If x=-2 the fuction is infinite so the domain goes from -infinite to -2

And from -2 to; + infinite

2006-11-19 15:28:01 · answer #2 · answered by maussy 7 · 0⤊ 1⤋

All Real Numbers, X cannot = 4

2006-11-19 15:23:03 · answer #3 · answered by lilstefon 2 · 0⤊ 2⤋