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36t^2 - 18tq + 9q^2

I don't know how to help my sister with her math homework.

2006-11-19 07:04:24 · 3 answers · asked by Jessica B 1 in Education & Reference Homework Help

3 answers

You have done some mistake while copying the problem.Please check it up.It may be 36l^2-36lq+9q^2 or something else.However I am doing ipresuming it to be 36l^2-36lq+9q^2

given exp.=9(4l^2-4lq+q^2)
=9{2l)^2-2.2l.q+(q)^2}
=9(2l-q)^2
The answer may also be written as {3(2l-q)}^2 or (6l-3q)^2

2006-11-19 11:17:08 · answer #1 · answered by alpha 7 · 0 0

Looking at it, the first thing I notice is the coefficients:
36, 18, 9

They are all multiples of 9. So let's divide those out first:

9(4t^2 - 2tq + q^2)

Hm, I was looking to factor it more than that, but it either can't be done or I'm just unable to figure it out right now.

btw, it's not a binomial; it's a trinomial.

2006-11-19 07:14:18 · answer #2 · answered by glurpy 7 · 0 0

First take out the common factor from all the terms:
9(4t^2 -2tq + q²).
Can you factor the term in brackets?
To answer this compute the discriminant, b²-4ac.
It is 4-16 < 0, so the answer is "no".

2006-11-19 07:16:48 · answer #3 · answered by steiner1745 7 · 0 0

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