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I have x=plus negative the square root of 5, but I don't know if it's right

2006-11-19 06:54:47 · 5 answers · asked by Charnissia S 1 in Science & Mathematics Mathematics

5 answers

2(x - 3) = 2

2(x - 3) / 2 = 8 / 2

(x - 3)² = 4

√(x - 3)² = √4

x - 3 = ± 2

x - 3 + 3 = 3 ± 2

x = 3 ± 2

- - - - - - - - -

Solving for ( + )

x = 3 + 2

X = 5

- - - - - - - - -

Solving for ( - )

x = 3 - 2

x = 1

- - - - - - - - -s-

2006-11-19 08:33:05 · answer #1 · answered by SAMUEL D 7 · 0 0

This equation has two solutions: X=5, or X=1. Try them. The steps: divide both sides by two; take the square root of both sides, and either X-3 = 2, or X-3 = 2 because 4 has two square roots. Solve these two equations for X and you'll have the two answers.

2006-11-19 15:01:17 · answer #2 · answered by TitoBob 7 · 0 0

Divide 8 by 2 first. this gives 4. then, take the square root of each side of the equation, which gives you (x-3) = pos/neg 2. Then, eliminate 3 by adding 3 on each side. You get two answers of plus 5, and negative one. Or, +5, -1.

+2 +3 gives +5
-2 +3 gives -1.

2006-11-19 15:00:52 · answer #3 · answered by Aldo 5 · 0 1

2(x-3)^2=8
divide both sides by 2
(x-3)^2=4
take the square root of both sides
x-3 = 2
add three to both sides
x = 5

2006-11-19 14:58:34 · answer #4 · answered by tj70555 2 · 0 1

2(x-3)^2 = 8
FOIL (First, Outside, Inside, Last)
2(x^2 - 6x + 9) = 8
2x^2 - 12x + 18 = 8
2x^2 - 12x + 10 = 0
divide everything by 2
x^2 - 6x + 5 = 0
factor
(x - 5)(x - 1) = 0
x = 1 and 5

2006-11-19 15:39:58 · answer #5 · answered by trackstarr59 3 · 0 0

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