4(3y+2m+1)=
-5(6a+3b-1)=
2006-11-19 06:00:01 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Even though somebody told you the answer, I'm going to explain how to do it so you know on other problems.
4(3y+2m+1)=
You have to take the number outside of the parenthesis, and multiply it to all the other numbers.
First you do 4 x 3y, because 3y is the first term.
That comes out to 12y.
The next one is 2m, so 4 x 2m= 8m
The last term is 1, so 4 x 1=4.
Add up all the numbers and the answer comes out to 12y+8m+3
Apply the same method to the 2nd problem
Hope this helps!
2006-11-19 06:10:18 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Just multiply the factor outside the parenthesis by each term inside.
4(3y+2m+1) = 12y + 8m + 4
-5(6a+3b-1) = -30a - 15b + 5
2006-11-19 14:04:21 · answer #2 · answered by tj70555 2 · 0⤊ 0⤋
The answer is the factor on the left times each of the terms in the parentheses, e.g. 4(3y+2m+1) = 12y + 8m + 4
2006-11-19 14:02:47 · answer #3 · answered by jacinablackbox 4 · 0⤊ 0⤋
4(3y+2m+1)=12y+8m+4
-5(6a+3b-1=-30a-15b+5
2006-11-19 14:18:25 · answer #4 · answered by arreed7 1 · 0⤊ 0⤋
Yes u need to use the distributive property.
The answer for the first question is:
12y+8m+4
The answer for the second question is:
-30a-15b+5
2006-11-19 14:04:27 · answer #5 · answered by Am 1 · 0⤊ 0⤋
don't u have any work other than asking this silly q's?
2006-11-19 14:19:38 · answer #6 · answered by fool 1 · 0⤊ 0⤋