Calculate DS in units of J/K for the formation of 1 mol of HI(g) from its elements in their standard states.
Work:
H(g) + I(g) > HI(g)
1mol HI * 206.33J/K - ( 1mol H(g)*114.60J/K + 1mol I(g)*180.67) =
-88.94 J/K
Calculate DS for the formation of 1 mole of PCl5(g) from the elements P4(s, white) and Cl2(g).
Work:
P4(s) + 10CL2(g) > 4PCl5
4*353J/K - (41.1 J/K + 10*223 J/K) = -859 J/K
Sulfur dioxide is released in the combustion of coal. Scrubbers remove much of the SO2 from the flue gases by reaction with lime slurries containing solid calcium hydroxide to form solid calcium sulfite and liquid water. Calculate So in units of J/K for the reaction of exactly one mole of sulfur dioxide gas in this scrubbing process at 298 K.
[So of calcium sulfite(s) = 101.4 J/mol.K]
My Work:
SO2 + calcium sulfite > CaSO4+H2O
(107+69.94) - (248.1+101.4) = -173 J/K
being that its at 298K I dont think i need to use G=H-TS
2006-11-19
05:16:06
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3 answers
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asked by
jnieves01
1
in
Science & Mathematics
➔ Chemistry
I think my problems lay with possibly the formula's I used to look up dS values. They look alright.
Oh yea, and I don't want people to think i'm asking someone to do my homework for me, this is just 3 out of 28 that I already finished and got corrected.
If someone could just look over my work and tell me where I went wrong, that would be awesome.
Thanks :)
2006-11-19
05:18:17 ·
update #1
Oh wow...duh, yea that was one big brain fart. Started looking back over my equations after you guys pointed some stuff out, everything is all fixed now :)
Thankfully you hinted at what I was doing wrong, otherwise I would have been going wtf tommorow. (TEST!!)
2006-11-19
06:25:50 ·
update #2