Find the x-intercepts. y = x^2 + 7x + 4?

Question

Find the x-intercepts. y = x^2 + 7x + 4

Answer 1

set y=0
solve quadratic eqn
quadratic eqn

-7 +- (49-16)^.5
-------------------
2
= (-7 +- 33^.5)/2

Answer 2

because the X-axis has a pair (x,y) with y=0 that is all the dots on the axis have a pair (x,0). So to find the answer you definetly should have Y=0 because only then will the interception be on the x-axis.

so because of that you'll have "y=0" and "y=x^2 +7x +4"
so when you combine you have 0=x^2 +7x +4
when resolved with the quadratic formula
(you can have none, one or two answers)
In this case we have two answer for the x part of the pair (x,y)
(remember we know y=0)

so the first answer is x1= -6.36

the second answer is x2= -0.06

the point where it is intercepted are (-6.36,0) and (-0.06,0)
because Y=0 for all the dots on the x-axis

Answer 3

Solving the equation x^2 + 7x + 4 = 0 will give you the answers to your problem.

Use a=1 and b=7 in the quadratic formula.

Answer 4

You can use the formula for roots but if you look a root is obvious
x=-1 and you knaw that the products of root = c-a here 4

So tne second root is x = -4

Answer x=-1 And x = -4

Answer 5

x-intercepts are at y=0

Answer 6

There are two such points which can be found by setting y=0 and then applying the binomial theorem, which is really easy. You don't need me to do it for you, do you?

Answer 7

the x intercepts are (-6.36,0);(-0.06,0)
andthe y intercept is (0,4)